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Solve for R. C=1/9π n^2r
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For this, you are going to use natural log to solve for r. I am going to assume that your function looks like this: \[\frac{ 1 }{ 9 }\pi n^{2r} = C\] Follow these steps: 1. multiply 2. divide 3. take the natural log [NOTE: \[\ln(a)^P=pln(a)\] From this point, you should be able to solve use the algebra tricks similar to the previous steps to solve for 'r'. Let me know if you get stuck.
The r is suppose to be regular not up by the small 2
is that the question?\[C=\frac{1}{9}π n^2r\]
yes
\[C=\frac{1}{9}π n^2r\] multiply both by 9 \[9*C=\frac{1}{9}π n^2r*9\] \[9*C=π n^2r\] divide both sides by π n^2 \[\frac{1}{π n^2}9C=\frac{1}{π n^2}π n^2r\] \[\frac{1}{π n^2}9C=r\] \[\frac{9C}{π n^2}=r\]
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