Question

Determine the Descriminate of each equation, how many solutions does each equation have:
A:
4x^2-2x=10
B:
3x^2+3=6x

Answer 1

Hint:
1. If the discriminant is negative, then you have no solutions
2. If the discriminant is zero, then you have one solution.
3. If the discriminant is positive, then you have two solutions

Answer 2

Make sure you put the quadratic equations in standard form first before calculating the discriminant.

Answer 3

okay so 4x^2-2x -10=0

Answer 4

Yes, so are you going to try calculating the discriminant now?

Answer 5

so 2^2 - 4(4)(-10)
4 - 16(-10)
4 + 160
164?

Answer 6

Be careful. The b term is negative, not positive.

(-2)^2 - 4(4)(-10)
4 - 16(-10)
4 + 160
164

Answer 7

oh okay, I should have paid more attention to that. so the descriminant is 164 and their are two solutions

Answer 8

Also, you should probably get used to writing your steps in this manner:

(-2)^2 - 4(4)(-10)
= 4 - 16(-10)
= 4 -(-160) <---- This step shows the proper property of a positive number
= 4 + 160
= 164

Answer 9

okay will do, so the next one is
3x^2 + 3 = 6x
3x^2 - 6x + 3 = 0
(-6)^2 + 4(3)(3)
36 + 12(3)
36 + 36
72, two solutions right?

Answer 10

Looks right

Answer 11

okay thank you