A cold beer initially at 35ºF warms up to 40ºF in 3 min while sitting in a room of temperature 70ºF. How warm will the beer be if left out for 20 min
Now if I remember correctly, temperate changes at an exponential rate, because it is a differential equation.
Yep. Go on...
That is \[ \frac{dT}{dt} = kT \]Where big \(T\) is temperature and \(t\) is time. So we need to solve: \[ T(t) = T_0e^{kt} \]
We know \(T_0 = 35^\circ F\) and \(T(3) = 40^\circ F\). We'll let \(t\) be in minutes.
So we find \(k\) given that:\[ \Large 40 = 35 e^{k(3)} \]
I think you know how to do the rest.
You're good :)
I'm not that good, it's just I've seen problems like this around here and by now they're relatively easy.
I really need to brush up on my vector calculus though. Not enough questions like that on this site.
up to multiple integrals or r u referring to stokes theorem, line integrals, and surface integrals?
I recently went over limits, derivatives, and integrals very very closely to get rid of any misconception I might have had. I wanna do the same with vector functions, multiple integrals, surface integrals, ect.
I can post one or 2 up if you want to try it? I'll help guide you the best I can if you have time right now.
Sure, that would be fun.
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