Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Calculate the products AB and BA to verify that B is the inverse of A.

OpenStudy (anonymous):

Do you know how to multiply matrices? This looks like it is just matrix multiplication.

OpenStudy (anonymous):

\[A= \left[\begin{matrix}6 & -5 \\ 1 & -1\end{matrix}\right] B= \left[\begin{matrix}1 & -5 \\ 1 & -6\end{matrix}\right]\]

OpenStudy (anonymous):

AB = ? BA= ?

OpenStudy (anonymous):

who can solve it?

OpenStudy (anonymous):

http://www.purplemath.com/modules/mtrxmult.htm

OpenStudy (anonymous):

and please give me the equation so I can try

OpenStudy (anonymous):

Read the link I gave. It is not a simple formula.

OpenStudy (anonymous):

yes looks long and difficult I'll give it a try.

OpenStudy (anonymous):

crap I don't know

OpenStudy (anonymous):

can anyone give me the answer if possible ?

OpenStudy (unklerhaukus):

\[AB= \left[\begin{matrix}6 & \color\red{-5} \\ \color{blue}{1} & \color{green}{-1}\end{matrix}\right]\left[\begin{matrix}\color{teal}{1} & \color{orange}{-5} \\ \color{\pink}{1} & \color{purple}{-6}\end{matrix}\right]\]\[\qquad=\left[\begin{matrix}(6\times\color{teal}{1})+(\color\red{-5}\times\color{\pink}{1}) && (6\times \color{orange}{-5})+(\color\red{-5}\times\color{purple}{-6}) \\\\ (\color{blue}{1}\times\color{teal}{1})+(\color{green}{-1}\times\color{\pink}{1}) && (\color{blue}{1}\times \color{orange}{-5})+(\color{green}{-1}\times\color{purple}{-6})\end{matrix}\right]\]

OpenStudy (anonymous):

okay what do I do now

OpenStudy (anonymous):

what do I do with those number?

OpenStudy (unklerhaukus):

multiply

OpenStudy (unklerhaukus):

then add

OpenStudy (anonymous):

okay let me try

OpenStudy (unklerhaukus):

you should get a nice simple matrix with four elements

OpenStudy (anonymous):

is the answer 0 0 0 1

OpenStudy (anonymous):

not sure if I did it right?

OpenStudy (unklerhaukus):

that is almost correct, one of the elements isn't right

OpenStudy (anonymous):

let me check again gah I hate matrix

OpenStudy (anonymous):

1 0 0 1

OpenStudy (unklerhaukus):

good stuff

OpenStudy (anonymous):

thanks Unkle so with BA what should I do for that one?

OpenStudy (anonymous):

the opposite ?

OpenStudy (unklerhaukus):

now you have to calculate \[BA= \left[\begin{matrix}\color{teal}{1} & \color{orange}{-5} \\ \color{\pink}{1} & \color{purple}{-6}\end{matrix}\right]\left[\begin{matrix}6 & \color\red{-5} \\ \color{blue}{1} & \color{green}{-1}\end{matrix}\right]\]

OpenStudy (unklerhaukus):

use the same method,

OpenStudy (anonymous):

oo that's why you gave me the colors huh

OpenStudy (anonymous):

is it the same thing as aB?

OpenStudy (anonymous):

you are the master thank you!

OpenStudy (unklerhaukus):

yeah , they are the same in this case, when AB=BA=I the matrices A and B are inverse of one another however in general, AB≠BA

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!