Calculate the products AB and BA to verify that B is the inverse of A.
Do you know how to multiply matrices? This looks like it is just matrix multiplication.
\[A= \left[\begin{matrix}6 & -5 \\ 1 & -1\end{matrix}\right] B= \left[\begin{matrix}1 & -5 \\ 1 & -6\end{matrix}\right]\]
AB = ? BA= ?
who can solve it?
and please give me the equation so I can try
Read the link I gave. It is not a simple formula.
yes looks long and difficult I'll give it a try.
crap I don't know
can anyone give me the answer if possible ?
\[AB= \left[\begin{matrix}6 & \color\red{-5} \\ \color{blue}{1} & \color{green}{-1}\end{matrix}\right]\left[\begin{matrix}\color{teal}{1} & \color{orange}{-5} \\ \color{\pink}{1} & \color{purple}{-6}\end{matrix}\right]\]\[\qquad=\left[\begin{matrix}(6\times\color{teal}{1})+(\color\red{-5}\times\color{\pink}{1}) && (6\times \color{orange}{-5})+(\color\red{-5}\times\color{purple}{-6}) \\\\ (\color{blue}{1}\times\color{teal}{1})+(\color{green}{-1}\times\color{\pink}{1}) && (\color{blue}{1}\times \color{orange}{-5})+(\color{green}{-1}\times\color{purple}{-6})\end{matrix}\right]\]
okay what do I do now
what do I do with those number?
multiply
then add
okay let me try
you should get a nice simple matrix with four elements
is the answer 0 0 0 1
not sure if I did it right?
that is almost correct, one of the elements isn't right
let me check again gah I hate matrix
1 0 0 1
good stuff
thanks Unkle so with BA what should I do for that one?
the opposite ?
now you have to calculate \[BA= \left[\begin{matrix}\color{teal}{1} & \color{orange}{-5} \\ \color{\pink}{1} & \color{purple}{-6}\end{matrix}\right]\left[\begin{matrix}6 & \color\red{-5} \\ \color{blue}{1} & \color{green}{-1}\end{matrix}\right]\]
use the same method,
oo that's why you gave me the colors huh
is it the same thing as aB?
you are the master thank you!
yeah , they are the same in this case, when AB=BA=I the matrices A and B are inverse of one another however in general, AB≠BA
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