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OpenStudy (dls):

What are the favourable conditions for the melting of ice?

OpenStudy (dls):

HT,HP HT,LP LT,HP LT,LP

OpenStudy (dls):

its definitely high temperature but what about pressure..?

OpenStudy (shubhamsrg):

HP wont allow the molecules to breakthrough from vander vall's forces i guess so wont melt easily.. i'd say HT,LP

OpenStudy (dls):

ITS HP HT!!

OpenStudy (vincent-lyon.fr):

HP will favour ice melting because liquid water occupies less space than ice does.

OpenStudy (shubhamsrg):

hmmm.. :/

OpenStudy (shubhamsrg):

sir please elaborate ?

OpenStudy (dls):

exactly

OpenStudy (shubhamsrg):

i was just trying to compare with KTOG , is there a flaw in my logic ? i mean ofcorse there is flaw..whats the flaw ?

OpenStudy (vincent-lyon.fr):

Have a look at water's phase diagram. You will see that to go from solid to liquid, you will have to go right or/and up. http://serc.carleton.edu/images/research_education/equilibria/h2o_phase_diagram_-_color.v2.jpg

OpenStudy (shubhamsrg):

alright, the experimental data favors your conclusion, i didnt understand the logic : " HP will favour ice melting because liquid water occupies less space than ice does."

OpenStudy (dls):

exactly

OpenStudy (vincent-lyon.fr):

I could have said: density of water is greater than density of ice.

OpenStudy (shubhamsrg):

then why HP ?

OpenStudy (shubhamsrg):

relation between HP and space occupied ?

OpenStudy (dls):

exactly

OpenStudy (vincent-lyon.fr):

Reason 1 is in the sign of dP/dT along the solidification curve. Reason of reason 1 is in the Clapeyron relation. http://en.wikipedia.org/wiki/Clausius%E2%80%93Clapeyron_relation

OpenStudy (shubhamsrg):

so if i say, to convert any matter from 1 state to another, if the latter one occupies more space than former, HP would favor it.. ?

OpenStudy (dls):

exactly

OpenStudy (dls):

you can say like this..

OpenStudy (dls):

Solid(higher volume)<==>Liquid(lower volume) Solis whose volume decreases on melting.example..ice..diamond..carborudnum..magnesium nitride and quartz.. the process of melting is facilitated at HP..thus melting point becmes high..melting point lowers..

OpenStudy (dls):

\[Volume = \frac{k}{pressure}\]

OpenStudy (dls):

n,t =constant..

OpenStudy (dls):

now think about it

OpenStudy (dls):

volume kam hogi..solids=>liquids pressure zada denge to zada ice formation hoga

OpenStudy (shubhamsrg):

density of ice< density of water volume = mass/density for same mass, volume of ice is more, hence at constant temp, pressure of ice is less than water ice -> water p1 p2 p1 < p2 pressure increases. according to le chatliers principle, shouldnt decreasing pressure or LP favor the process ?

OpenStudy (dls):

H2O(s)===>H2O(l) less pressure ===>high pressure reaction has to go forward.. oh yes :p

OpenStudy (shubhamsrg):

there is some mistake 110% in our logic,,damn we are pathetic in studies! :(

OpenStudy (dls):

:'(

OpenStudy (dls):

Solid===>Liquid high temp===>low temp so u would say less temperature favours melting? O.O

OpenStudy (shubhamsrg):

ice -> water temp doesnt change.. temp changes only after 100% ice is melted to water, otherwise its constant at 0 degree

OpenStudy (dls):

:/

OpenStudy (vincent-lyon.fr):

I do not understand your discussion. The temperature and the pressure mentioned are the external P and T imposed to a compound. They correspond to a point in the phase diagram. If the point is in an area with a certain stable state and if the body is actually in another state, then it is out of equilibrium and its state will evolve, provided there is enough energy available to do so.

OpenStudy (vincent-lyon.fr):

So melting of ice will be all the more easy if you increase temperature and pressure \( \textit {of the environment}\). Boiling of water will be easier if y ou increase temperature and/or decrease pressure \( \textit {of the environment}\)..

OpenStudy (shubhamsrg):

i seem to get a hang of it..thanks a lot for your time sir! :)

OpenStudy (dls):

IM LOST

OpenStudy (shubhamsrg):

in layman terms, this can be seen as HP would mean pushing molecules more inside right, which does explain boiling..right ?

OpenStudy (anonymous):

look at it this way. density of ice < density of water. which tells us that in the same volume V, we have more molecules of water than ice. ie, Mi < Mw where Mi = no of molecules of ice in volume V Mw = no of molecules of water in V so, to convert ice into water, we have to INCREASE the no of molecules in the given volume. how do u do that? by pushing them inside. in other words, INCREASING the PRESSURE. get it?

OpenStudy (dls):

processing

OpenStudy (shubhamsrg):

i see..layman language me mujhe samjh aa gaya! cool.. B|

OpenStudy (dls):

what u explained seems kinda jugaadu o.O is that the real reason?

OpenStudy (dls):

if that is real then what is what vincent explained ._.

OpenStudy (anonymous):

sir explained the scientific reasoning. i just made the language simpler. both are actual facts.

OpenStudy (dls):

i didnt understand what he said :/

OpenStudy (anonymous):

thats why i used simpler language. u understood what happens, right? thats enough then.

OpenStudy (dls):

:/ okay

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