A quantity of gas expands under pressure p N/m^2 according to the law p*v^0.9 = 300 where v m^3 is the volume of gas under pressure p N/m^2. WHAT IS THE AVERAGE PRESSURE AS THE VOLUME CHANGS FROM 1/2 m^2 to 1m^2?

Question

anonymous · Answer

So we have $ \large pv^{0.9}=300$?

anonymous · Answer

"AS THE VOLUME CHANGS FROM 1/2 m^2 to 1m^2"

Volume is not measured in m^2

anonymous · Answer

its a typo

anonymous · Answer

which part is the typo?

anonymous · Answer

um.. my book says.. squared.. i dont know why.. volume should be cubed right?

anonymous · Answer

Yes, volume is cubed, surface area is squared.

anonymous · Answer

then can you please produce an equation with an assumption of the unit is cubed?

anonymous · Answer

Sure.

anonymous · Answer

thank you

anonymous · Answer

Sorry, open study crashed on me.

anonymous · Answer

thank you :)

anonymous · Answer

Hold on...

anonymous · Answer

No, that isn't right.

anonymous · Answer

Yeah, the units aren't measuring up.

anonymous · Answer

I originally was thinking something along the lines of: $$ \Large
\overline{p} =\frac{1}{v_f-v_i} \int_{v_i}^{v_f}p(v)dv
$$

anonymous · Answer

@ksw19372
Do you have a means of checking your answer?