Help solve this integration
\[\int\limits_{0}^{2} \int\limits_{x}^{2} x \sqrt{1+y^3} dydx\]
so, u need help with integrating \(\sqrt{1+y^3}dy\) or do u want to change the order of integration ?
just evaluate it
what have u tried ?
i just use u = 1+y^3 then differential it
i think change of order is necessary.
could you tell me a bit more plz
\(\int\limits_{x=0}^{x=2} \int\limits_{y=x}^{y=2} x \sqrt{1+y^3} dydx\) to change the order of integration, we need to find the region in which integration is performed, so, first, can u plot the lines y=x and y=2 ??
yes
so try to plot the 4 lines, y=x to y=2 and x=0 to x=2 u'll get a closed region, can u tell me what region u get using the drawing tool ?
it's a triangle
yes.
|dw:1356616272089:dw| right ?
yes
then
|dw:1356616346863:dw| can i write that region again as \(x=0 \: to \: x=y \\ y=0\: to \:y=2\)
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