A triangle has one side 6cm and the sum of other two sides is 10cm.Find the maximum possible area of the triangle.
owing to the symmetry , either 6,6,4 should have max area of 5,5,6 am just saying,,anyone would like to confirm ?
or* 5,5,6
try heron's formula .. maximize it
|dw:1356617080153:dw| this can also be viewed as : the sum of sides is constant , so the fixed points are the focii of an ellipse where distance between the focii = 6 and sum of distances from focii to circumference is 10 clearly area is max when other side is at the edge of minor axis..
other point* is at the edge of minor axis
http://www.wolframalpha.com/input/?i=maximize+sqrt%288+*+2*+%288-x%29%288-%2810-x%29%29
allow me to put in other words, let P be a point on the ellipse, |dw:1356617902562:dw| area = 1/2 (height)(6) = 3 height more the height, more the area height is ofcorse max at the minor axis end,and hence your ans, knowledge of eqn of ellipse , or anything legit will allow you to calculate length of minor axis and hence every other required detail..
but this area is of right angle
|dw:1356618142674:dw| area = 1/2 hb
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