Question

Solve this Series-Paralle circuit question please, i attached it in

Answer 1

This problem is clearer if the resistor network is redrawn as follows:

There are three resistors in parallel, 18k (4k + 14k = 18k), 9k and 12k. The total conductance of this parallel combination can be found by adding the conductances:
\[\frac{1}{R _{total}}=\frac{1}{18\times 10^{3}}+\frac{1}{9\times 10^{3}}+\frac{1}{12\times 10^{3}}\]
The required voltage is then found by multiplying the total circuit resistance by the current:
\[V _{o}=(R _{total}+2\times 10^{3})\times 2\times 10^{-3}\]