2/3(x+2)-1/4(x-2) Which is an equivalent expression to the one above? (1) 11/12x + 22/12 (2) 11/12x + 10/12 (3) 5/12x + 10/12 (4) 5/12x + 22/12
I assume this is \[ \frac{2}{3(x+2)} - \frac{1}{4(x-2)} \]
if so, multiply the first fraction by 4(x-2)/4(x-2) (and notice you are doing (a+b)(a-b)= a^2-b^2 ) multiply the 2nd fraction by 3(x+2)/3(x+2)
or is it \[ \frac{2}{3}(x+2) - \frac{1}{4}(x-2) \]
Yes phi its the second one
\[2/3(x+2)-1/4(x-2)\]
then distribute the 2/3 (that means multiply 2/3 times x and times 2 do the same for -1/4 then you have to "combine" like terms can you do that?
Ill try one minute please
Ill try one minute please
so 2/3x+1.33333-1/4x+0.25
yes, but I am guessing they want you to stick with fractions (this question is really about fractions) so (2/3)x + 4/3 - (1/4)x + 2/4 notice that last term is 2/4 (or 1/2) not 0.25 (which means 1/4)
oh I see
now combine 2/3 of an x minus 1/4 of an x the common denominator is 12
8/12 and 3/12
yes so you now have (8/12) x - (3/12) x +4/3 - 2/4
you can now subtract 8/12 x - 3/12 x to get 5/12 x
Isnt it 8/12x+3/12x+4/3+1/2
Or no need to simplify the 2/4
Im confused because dont you have to add to get rid of the -3/12
Wait nevermind I not understand
don't lose track of your signs. start at the beginning (2/3)x + 4/3 - (1/4)x + 2/4 you changed the 2/3 to 8/12 and the 1/4 to 3/12 to get (8/12)x + 4/3 - (3/12) x + 2/4 now "collect terms" meaning put the x terms next to each other. notice the -3/12 x is negative
So now we have (5/12) + (4/3) - (1/2)
so like combining them.. pretty much simplifying the expression
you mean (5/12)x + (4/3) - (1/2) don't leave out the x now do the same for the numbers, use 12 for the common denominator (because all the answers seem to be using 12)
I have the x on my paper just that I forgot to type it
EDIT: (5/12x) + (16/12) - (6/12)
almost done...
(5/12x) + (10/12)?
yes. If you are rusty with fractions see http://www.khanacademy.org/math/arithmetic/fractions take a peak at some of the videos.
Yeah i am never rusty with fractions, all these acuity exams I need to improve with them
The acuity exams say thats what I need to improve in
Thank you so much for your help you have earned a fan
thanks.
Can you help my out with two more problems ill be posting them now
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