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find lim x-->0 (sin(3x))/x
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\[\lim_{x \rightarrow 0} \frac{ \sin(3x) }{ x }\]
this need to be rewritten and use the following limit fact \[\lim_{\theta \rightarrow 0} \frac{\sin(\theta)}{\theta} = 1\] so rewriting the fraction so the denominator is the same as the angle it can be written as \[\lim_{x \rightarrow 0}\frac{3\sin(3x)}{3x}\] I let h = 3x in the limit below... \[\ = 3 \times \lim_{h \rightarrow 0}\frac{\sin(h)}{h} = 3 \times 1\]
ok thanks.
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