Two times an unknown number is at least 2, and 6 more than the number exceeds 9. Find all possible
values for the unknown number.

Question

Two times an unknown number is at least 2, and 6 more than the number exceeds 9. Find all possible
values for the unknown number.

anonymous · Answer

Hi

anonymous · Answer

Ok, so two inequalities this time. 2 times x is at least 2 - how would you write that?

anonymous · Answer

And hi

anonymous · Answer

2x >= 2

anonymous · Answer

Right, now for the second one - 6 more than x exceeds 9. What's that symbolically?

anonymous · Answer

-6 + x....iidk what exceed symbolizes

anonymous · Answer

Exceed is just greater than. And sorry, that was a dash, not a negative. It's positive 6.

anonymous · Answer

oh :P....|dw:1356662727144:dw|

anonymous · Answer

x > 3

anonymous · Answer

Right, good. And simplify the first one?

anonymous · Answer

idk....:P

anonymous · Answer

Well, you want x to be alone, so try dividing both sides by 2. 2x >= 2, just so you don't have to scroll up and down

anonymous · Answer

x >= 1

anonymous · Answer

Right. So x >= 1, and x >3. Do you have to write both, or can you simplify further?

anonymous · Answer

ummm...heres the answere chiocec...

anonymous · Answer

[A] mx x ÎR, x ³ 1r [B] mx x ÎR, x > 3r
[C] mx x ÎR, 1 £ x < 3r [D] mx x ÎR, 1 < x £ 3r

anonymous · Answer

Woh, that didn't really come out right, did it....

anonymous · Answer

a. x >= 1 b. 1 <= x <= 3 c. x >3 d. 1 < x <= 3

anonymous · Answer

Ok, so which one seems right?

anonymous · Answer

sorry sir :P...i feel stupid

anonymous · Answer

a