Question

Factor fully:

Answer 1

\[\huge x^3+2x^2-18x-40\]

Answer 2

are you sure you're not missing anything?

Answer 3

yes i am sure

Answer 4

x^2(x+2)-2(9x+20)
(x^2-2)(x-2)(9x+20)
you could do that...

Answer 5

There is a mistake somewhere... the answer needs to be\[\huge \color{green}{(x+4)}\color{red}{(x^2-2x-\color{blue}{10})}\]

Answer 6

i am looking

Answer 7

\(x^3+2x^2-18x-40 \\ x^3+4x^2-2x^2 -10x-8x-40 \\(x^3-2x^2-10x)+(4x^2-8x-40) \\ ...\)

Answer 8

because what u did after \(\color{green}{x}\color{red}{(}x^2+2x\color{blue}{-2 \color{red}{)+\color{green}{4}(}-4x}-10\color{red}{)}\)
you cannot factor out x+4 ...
a(c)+b(d) does not equal (a+b)(c+d)

Answer 9

I think I know. You cannot factor out the (x+4) from mine because the other quantities ar not the same

Answer 10

excatly