Mathematics
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OpenStudy (anonymous):
Can someone help me solve this?? geometry
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OpenStudy (anonymous):
OpenStudy (anonymous):
u know Trignometry
OpenStudy (anonymous):
no i don't
hartnn (hartnn):
pythagoras theorem ?
OpenStudy (anonymous):
you mean (a)2 + (b)2 = (c)2 ??
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hartnn (hartnn):
can u find AC first ? ?
hartnn (hartnn):
yes.
OpenStudy (anonymous):
one sec let me calculate
OpenStudy (anonymous):
i got 18. something something something
hartnn (hartnn):
using pythagoras again, find AD
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OpenStudy (anonymous):
or i got 16(2) + 10(2) = 356 ...
hartnn (hartnn):
no, 16 is hypotenuse, so it'll be \(\sqrt{16^2-10^2}\)
hartnn (hartnn):
got that^ ?
OpenStudy (anonymous):
i first did 16(2)-10(2) on the calc and i got 156
hartnn (hartnn):
right, so keep \(AC^2=156\)
now using pythagoras again, find AD .
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OpenStudy (anonymous):
how??
hartnn (hartnn):
pythagoras theorem in triangle ACD with CD = 16-x
OpenStudy (anonymous):
okay now I'm stuck. i really don't get it. if AC2=156 how am i suppose to find D with one number??
hartnn (hartnn):
ok, let me write steps using pythagoras theorem in both triangles.
ACD and ABD
\(AD^2=AC^2-CD^2 \\AD^2=AB^2-BD^2 \\ \implies AC^2-CD^2 =AB^2-BD^2 \)
hartnn (hartnn):
CD = 16-x , BD =x
only x is unknown
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hartnn (hartnn):
can u find 'x' now ?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
i give up.
hartnn (hartnn):
heyyy
hartnn (hartnn):
\(156 -(16-x)^2=x^2+10^2\)
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hartnn (hartnn):
\(156-256+32x+x^2=x^2+100 \\-100+32x=100 \\32x=200\)
hartnn (hartnn):
still can't find 'x' ? @ashley753 ?
x= 200/32 = 25/4
OpenStudy (anonymous):
i found x and the answer was C thank you!