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Mathematics 7 Online
OpenStudy (anonymous):

Can someone help me solve this?? geometry

OpenStudy (anonymous):

OpenStudy (anonymous):

u know Trignometry

OpenStudy (anonymous):

no i don't

hartnn (hartnn):

pythagoras theorem ?

OpenStudy (anonymous):

you mean (a)2 + (b)2 = (c)2 ??

hartnn (hartnn):

can u find AC first ? ?

hartnn (hartnn):

yes.

OpenStudy (anonymous):

one sec let me calculate

OpenStudy (anonymous):

i got 18. something something something

hartnn (hartnn):

using pythagoras again, find AD

OpenStudy (anonymous):

or i got 16(2) + 10(2) = 356 ...

hartnn (hartnn):

no, 16 is hypotenuse, so it'll be \(\sqrt{16^2-10^2}\)

hartnn (hartnn):

got that^ ?

OpenStudy (anonymous):

i first did 16(2)-10(2) on the calc and i got 156

hartnn (hartnn):

right, so keep \(AC^2=156\) now using pythagoras again, find AD .

OpenStudy (anonymous):

how??

hartnn (hartnn):

pythagoras theorem in triangle ACD with CD = 16-x

OpenStudy (anonymous):

okay now I'm stuck. i really don't get it. if AC2=156 how am i suppose to find D with one number??

hartnn (hartnn):

ok, let me write steps using pythagoras theorem in both triangles. ACD and ABD \(AD^2=AC^2-CD^2 \\AD^2=AB^2-BD^2 \\ \implies AC^2-CD^2 =AB^2-BD^2 \)

hartnn (hartnn):

CD = 16-x , BD =x only x is unknown

hartnn (hartnn):

can u find 'x' now ?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

i give up.

hartnn (hartnn):

heyyy

hartnn (hartnn):

\(156 -(16-x)^2=x^2+10^2\)

hartnn (hartnn):

\(156-256+32x+x^2=x^2+100 \\-100+32x=100 \\32x=200\)

hartnn (hartnn):

still can't find 'x' ? @ashley753 ? x= 200/32 = 25/4

OpenStudy (anonymous):

i found x and the answer was C thank you!

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