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Mathematics 12 Online
OpenStudy (ksaimouli):

find g(-1) and g''(-1)

OpenStudy (ksaimouli):

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OpenStudy (ksaimouli):

\[g(x)=\int\limits_{0}^{x}f(t) dt\]

OpenStudy (ksaimouli):

graph above is f

OpenStudy (ksaimouli):

|dw:1356718836761:dw|

OpenStudy (ksaimouli):

find g(-1)

OpenStudy (ksaimouli):

@hartnn

hartnn (hartnn):

can u find the point of intersection of those 2 lines ? or, equation of those lines ??

OpenStudy (mathmate):

Is g(x) a constant? I don't see x in the definition of g(x). Does f(x) = 0 for x>2, or does it decrease forever?

OpenStudy (ksaimouli):

@hba

OpenStudy (ksaimouli):

i know that f'(-1)=0

OpenStudy (ksaimouli):

what i have no idea how to find the f(-1)

hartnn (hartnn):

|dw:1356720077842:dw|

OpenStudy (ksaimouli):

slope is 3

OpenStudy (hba):

Now you can find the equation :)

hartnn (hartnn):

and u also have point , so equation is ?

OpenStudy (ksaimouli):

y=3x+3

hartnn (hartnn):

x=-1 thats your f(t) for 0 to -1

hartnn (hartnn):

\(g(-1)=\int\limits_{0}^{-1}(3x+3) dt\)

hartnn (hartnn):

can u find g(-1) now

OpenStudy (ksaimouli):

yes

hartnn (hartnn):

good :)

OpenStudy (hba):

-(3x+3)

OpenStudy (ksaimouli):

-3/2

OpenStudy (ksaimouli):

what about f''(-1)

hartnn (hartnn):

u sure about -3/2 ??

OpenStudy (ksaimouli):

yes

OpenStudy (ksaimouli):

|dw:1356720626985:dw|

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