Question

For the reaction: C(s) + 2H2(g) ⇄ CH4(g), Kp is 0.262 at 1000oC. At equilibrium, the partial pressure PH2 = 1.22 atm. Calculate the equilibrium partial pressure of CH4(g).

Answer 1

Kp = PP [CH4] / PP[H2] ^2



PP [CH4] = Kp * PP[H2] ^2


= 0.262 * (1.22)^2

Answer 2

i forget that pure solids and pure liquids are materials whose concentration doesn’t change during the course of a reaction. Because their concentration doesn’t change, solids and liquids are not included in the equilibrium constant expression..

Answer 3

Yup..)