PLEASE HELP!!! Make a table of values, and graph j(x) = 2 x - 2. Describe the asymptote. Tell how the graph is transformed from the graph of f(x) = 2 x.

Question

jim_thompson5910 · Answer

is it

$$\Large j(x) = \frac{2}{x-2}$$

or

$$\Large j(x) = \frac{2}{x}-2$$

??

anonymous · Answer

its j(x)= 2^x-2, sorry i forgot to write it like that

jim_thompson5910 · Answer

so 

$$\Large f(x) = 2^{x}$$

and

$$\Large j(x) = 2^{x-2}$$

??

or is j(x)

$$\Large j(x) = 2^{x}-2$$

anonymous · Answer

the first one is right, I know that it is transformed 2 units to the right, but i cant find the asymptote

jim_thompson5910 · Answer

you are correct, to go from 

$$\Large f(x) = 2^{x}$$

to 

$$\Large j(x) = 2^{x-2}$$

you translate everything 2 units to the right

jim_thompson5910 · Answer

the asymptote is a horizontal asymptote

this is because as x gets smaller and smaller (in the negative direction), $\Large 2^{x}$ becomes smaller and smaller (and it essentially becomes 0)

jim_thompson5910 · Answer

so the horizontal asymptote for $$\Large f(x) = 2^{x}$$ is y = 0

anonymous · Answer

Thank you so much, my class didn't explain how to find an asymptote or even what it is so it was really confusing, thanks again :)

jim_thompson5910 · Answer

the horizontal asymptote for $$\Large j(x) = 2^{x-2}$$ is also y = 0

jim_thompson5910 · Answer

because shifting everything to the right 2 units will NOT shift the horizontal asymptote