Question

What are the first and last terms of this geometric series?

Answer 1

Look at the summation sign, where i goes from 1 to 6.
So for the first term substitute i=1 in \( 5 *2^{2i-1} \) to get \( 5 *2^{2-1}=5*2=10 \).
For the last term, i=6, so \( 5 *2^{2i-1} = 5*2^{2*6-1}=5*2^{11} = ?\)
I'll leave that calculation to you.