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Mathematics 14 Online
OpenStudy (anonymous):

Geometry help http://tinypic.com/r/fw663d/6 1. Calculate the length of DE 2. Calculate the area of circle Q 3. Approximate the area of the circle segment bounded by segement DE and arc DE 4. Calculate the circumfrence of circle Q 5. Calculate the area or the sector bounded by segment DQ, segment EQ and arc DE

OpenStudy (anonymous):

1) use the rule of cosines 2)pi(15)squared 3)since the area of the sector is (72pi/180)(15squared)/2, and you can calculate the area of the triangle through the equation 15*15*sin(72degrees), deducting them, should give you the area you want

OpenStudy (anonymous):

4)2pi(15)=30pi 5)They are either kidding or they are trying to test your skill for spotting pentagons, since the angle given is 72 degrees. Using that, you can also find the answer in part 3 and then you can answer part 5. which grade is this question for?

OpenStudy (anonymous):

What is the rule of cosines?

OpenStudy (anonymous):

in a circle with sides abc the length of the side c facing angle theta is equal to : (a squared)+(b squared)-ab costheta

OpenStudy (anonymous):

sorry, there is a small mistake, you should have : -2ab costheta instead of -ab I forgot about the coefficient of 2

OpenStudy (anonymous):

did you get the last note? IT SHOULD BE c=(a squared)+(b squared)-2ab cos theta

OpenStudy (anonymous):

confirm that you understood the right form

OpenStudy (anonymous):

Yes. Hold on for a minute im gonna solve it

OpenStudy (anonymous):

Is it 10.8 pi?

OpenStudy (anonymous):

I missed something its calculate the arc of DE

OpenStudy (anonymous):

which part?

OpenStudy (anonymous):

arc of DE is r*theta [theta in radians] arc DE=15*72pi/180

OpenStudy (anonymous):

the answer for DE is 31.4159 which is 10pi

OpenStudy (anonymous):

Number 3 im getting 213. something which isnt the anwser. Can you show me the steps?

OpenStudy (anonymous):

wait a sec

OpenStudy (anonymous):

1) find the area of the triangle. 2) multiply it by 5 to find the area of the pentagon inside the circle 3) deduct the area of the circle from the area of the pentagon 4) divide that result of subtraction from step 3 by 5 5) the answer is the area of the portion between the arc and the side of the triangle facing the angle 72.

OpenStudy (anonymous):

tell me whether that works or not

OpenStudy (anonymous):

Number 1 I got 10.8 pi Number 2 I got 225 pi Number 3 I got 34.4 pi Number 4 i got 30 pi Number 5 I got 6 pi Do those look right to you?

OpenStudy (anonymous):

1)I'm not sure how you're finding it, but I found it to be 17.63, using law of cosines 2) correct wait for the rest....

OpenStudy (anonymous):

3)34.377819 4)correct 5)sum the area you found to solve for part 3 (106.99385) with the final answer of part 3. the result would be 141.371669

OpenStudy (anonymous):

let me check my answers using another way...

OpenStudy (anonymous):

yes, it is perfectly correct

OpenStudy (anonymous):

tell me your doubts

OpenStudy (anonymous):

I remembered one more thing, The equation provided for law of cosines is equal to square of the length of that side. Therefore, to get the length, you have to take the square root of that equation. OK?

OpenStudy (anonymous):

Good luck

OpenStudy (anonymous):

Thank you for the help

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