Can someone show me how to use Simpson's Rule in integral (1/(x+1)^2)dx from 1 to 3?
\[\int\limits_{1}^{3} \frac{ x }{(x+1)^2 }dx\]
Never heard of it before.
Ok, here's Simpson's Rule: \[\int\limits_a^b f(x) dx \approx \frac{b-a}{6}(f(a)+4f(\frac{a+b}{2})+f(b))\] So in your case: \[\int\limits_1^3\frac{x}{(x+1)^2} dx \approx \frac{1}{3}(0.25+\frac{8}{9}+\frac{3}{16} )\] Plug and chug.
My teacher never taught Simpson's rule, so I looked at my textbook and I found the formula but since the formula is |dw:1356747242175:dw|
Oh, that's the composite Simpson's Rule. It goes 2, 4, 2, 4, etc.
it's n = 4
so it just repeats 2,4,2,4,2,4....until x(n) term right?
Right, so for n = 4, it would be 1, 2, 4, 1
ok thanks. that's all i needed. :)
Great, have fun integrating :P
haha thanks :D
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