I need help with a geometry question about the length of a median in a triangle.
where is the triangle?
let me attach a photo
there
I am unsure of how to approach this
U know pythagorean theorem?
yes
c^2=a^2+b^2
yes
use it find the base of the triangle
well i already tried that and got 6.4 for the entire base
so do i then divide 6.4 by 2 then Pythagorean theorum again
...
You couldn't get 6.4 for the base, because that's the hypotenuse
(6.4)^2 = (2.2)^2 + x^2 x=6.01
Thats the length of the entire base
Now, divide it by 2 and apply pythagorean theorem
got it?
lemme draw this right side up |dw:1356752775180:dw|
let's say that |dw:1356752872146:dw|
this is a two stepper. so \[2.2^2 + (2y)^2 = 6.4^2\] solve for y then do \[2.2^2 +y^2 = x^2\]
It is the distance between the point (0,2.2) and the point (a/2,0) The distance is d=sqrt(2.2**2+a**2/4) find a, the base of triangle, by Pythagoras
Thank you everyone, i'm just about to get this and will say what my answer is when i do
okay i got 3.7m, is that more or less right (i rounded a couple of numbers to 1 decimal place).
yes, x= 3.724 to 3 decimal places. Round to the nearest tenth (because the data was given to the nearest tenth, e.g. 6.4 and 2.2) so 3.7
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