Question

how to make p(x)=x^3+2x^2-6x-4 as a product of two factors?

Answer 1

u can use factor and remainder theorem to factorise it

Answer 2

how do u do that

Answer 3

first find the factors of 4
the factors of 4 are 1,2,4

Answer 4

thus put x =+1 or -1 or +2 or -2 or +4 or -4 to see that p(x) becomes 0

Answer 5

here for x=2
p(2) =(2)^3+2(2)^2-6(2)-4=8+8 -12-4=0
hence p(2) =0
thus x-2 is one of the factors

Answer 6

now u can divide x^3+2x^2-6x-4 by x-2 to get the other factors
or mere arrangement of terms will also give u the other factors
as follows

Answer 7

oh ok

Answer 8

p(x)=x^3+2x^2-6x-4
=x^2 -2x^2 +4x^2 -8x +2x
= x^2 (x-2) +4x(x-2) +2(x-2)
=(x-2)(x^2 +4x +2)

Answer 9

just factor.
p(x) = x^3+2x^2-6x-4
p(x) = x^2(x+2)-2(x+2)
p(x) = (x^2-2)(x+2)

Answer 10

@matricked thanks, thats what i got (:

Answer 11

welcome dear