Question

7/9, 7/3, 7, -21, 63,.... 9th term of following geometric sequence? Enter a whole number

Answer 1

you need to sind the common ratio 1st

\[\frac{T_{2}}{T_{1}} = \frac{T_{3}}{T_{2}}\]

when you know the common ratio

then \[T_{9} = ar^{n -1}\]

a = 1st term 7/9

r = common ratio

n = term number ( its 9)

Answer 2

what do you plug in for R?

Answer 3

you need to find it... what is each term being multiplyed by to get the next term..?

Answer 4

there may be an error in to sequence, is the 2nd term negative... as you have the 4th term as a negative..

Answer 5

-1/3

Answer 6

-3

Answer 7

7/9 * -1/3 = -7/27

so its not -1/3 just the reciprocal

Answer 8

yep thats it

so \[T_{9} = \frac{7}{9} \times (-3)^{9 -1}\]

the answer should be positive

Answer 9

i got 878.65, is that correct? or rounded 879

Answer 10

I got 5103

Answer 11

it should be a whole number answer.