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Find the most general function M(x,y) for the equation: M(x,y)dx +(x sec^2y- x/y)dy=0 so that the equation is exact
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is M(x,y) =tany -lny
For the equation 2 b exact, dM/dy must be equal to dN/dx. So, my 1st try is find dN/dx where\[N = ( x \sec ^{2}y -\frac{ x }{ y})\] therefore \[\frac{ dN }{ dx }= \sec ^{2}y -\frac{ 1 }{ y }\]
yup
Hw to get that ans? Can u pls explain further?
just integrate both sides
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So the next step is integrating dN/dx?
yup
and hence N=tany -lny +c
but it should be dN/dy
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