the period of a simple pendulum varies directly as the square root of its length if a pendulum 12 feet long has a period of 4 seconds find the period of a pendulum of length 3 feet? the number of aluminum cans used each year varies directly as the number of people using the cans . if 250 people use 60,000 cans in one year . how many cans are used in a place which has a populatoin of 850 000 ?
The equation for the period can be written as follows: \[T=k \times \sqrt{l}\] where T = the period, k = a constant of proportionality and l = the length. Substituting the given values into the equation enables us to find k as follows: \[4=k \times \sqrt{12}\] \[k=\frac{4}{\sqrt{12}}\] Now we have a value for k we can go back to the original equation and substitute to find the period of a pendulum of length 3 feet: \[T=\frac{4}{\sqrt{12}}\times \sqrt{3}\] where T is the period in seconds. Can you finish it now?
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