Question

What is the sum of this infinite geometric series?

Answer 1

If we bring the 12 to the front we get a sum of 1/4^i. Our first term, a = 1/4 and our common ratio is 1/4 since each consecutive term is 1/4th of the previous.

Using our equation we can get the summation as S = a / (1 - r) = 1/4 / (1 - 1/4)

Then we multiply this by the 12 we brought out earlier.

Our final solution is 12 * 1/4 / (1 - 1/4)

What do you get?

Answer 2

Is it 4?

Answer 3

Yes that's what I got

Answer 4

for sum of infinite GP S=a/(1-r) here a=3 and r=1/4 hence S=12/(1-1/4) =4

Answer 5

it is 4 (not 16 as i hv earlier mentioned)