Question

log3( log2 (logx 5))=0 ??

Answer 1

make use of these :
1) if log a b =c ,, (where a is base)
then a^c =b

2) log 1 =0 (for any base)

this should help..

Answer 2

Try to do this step by step: the last calculation yields 0:

\[\log_{3}(...)=0 \]so according to @shubhamsrg 's tip, the dots (...) are equal to 1.
This means:\[\log_{2}(...)=1\]
Now the dots (...) are equal to 2^1 = 2.
See? Maybe you can try the last step yourself!

Answer 3

OK, now we have:\[\log_{x} 5=2\]which means x² = 5, so x = ...

Answer 4

Thanks, I get it now.

Answer 5

aliter

log3( log2 (logx 5))=0 [bcoz log 1=0]
hence
( log2 (logx 5))=1 [bcoz log2 2=1 read as log of 2 base 2]
hence
logx 5=2
or x^2 = 5
or x= sqrt(5)

Answer 6

thank you