Question

Please wait for image. Logarithms

Answer 1

which one ?

Answer 2

Q16

Answer 3

for part (i), take log on both sides,
log p=.... ?

Answer 4

lg p = lg a^loga x ?

Answer 5

yes, now use, \(\log m^n=m \log n\)

Answer 6

sorry, n log m

Answer 7

what u get ?

Answer 8

lg p = loga x * lg a

Answer 9

write log, not lg
now use,
\(\huge \log_ab=\frac{\log b}{\log a}\)
so what is log_a x = ??

Answer 10

log x / log a

Answer 11

now substitute that in
log p = loga x * log a

Answer 12

I'm not sure what to do but is it:
log p = (log x/log a) * log a ?

Answer 13

really ?
just cancel out log a from numerator and denominator....
what remains ??

Answer 14

and yes, its that

Answer 15

shall i write out all steps ??

Answer 16

Oh wait I got it ><' Thank you so much! :)

Answer 17

u want part 2 also ??

Answer 18

Yup

Answer 19

\(If, x=\log_ab \implies b=a^x\)
so what about , q=log_4 3 ??

Answer 20

3 = 4^x

Answer 21

u mean 3=4^q ??

Answer 22

sorry yup

Answer 23

now u need 3^(1/q) =... ?
so what will u do ??

Answer 24

I'm not sure..?

Answer 25

raise both sides to (1/q) exponent...

Answer 26

How do you do that sorry

Answer 27

\(\huge 3^{(1/q)}= (4^q)^{1/q}\)

Answer 28

\(\huge (4^q)^{1/q}=.....?\)

Answer 29

4

Answer 30

right?

Answer 31

yes.

Answer 32

and you are done ..

Answer 33

okay thanks a lot!

Answer 34

welcome ^_^