Question

multiply
(6+4i)(9+i)=

Answer 1

Have you heard of FOIL?
The only extra thing you must remember is: wherever there's an i², replace it with -1.

Answer 2

First, Outer, Inner, Last

Answer 3

no

Answer 4

If you do FOIL method, you end up with:
54 + 6i+ 36i+ 4i^2
Combine like terms, you get 42i+54+4i^2
When there is an i^2, it = -1. So if you do 4(-1), you get -4
54-4+42i
50+42i

Answer 5

You must multiply every number in the left pair of brackets with each one in the right pair:
First: 6*9
Outer:6*i
Inner:4i*9
Last: 4i*i
Add everything up where possible, and remember: i²=-1

Answer 6

problem hav been solved?

Answer 7

im having trouble getting the answer

Answer 8

do u study complex number?

Answer 9

As @zaynahf calculated:

First: 54
Outer: 6i
Inner: 36i
Last: 4i² = 4*-1 = -4

Now complex numbers can be written as a+bi, a is the real part and b is the imaginary part.
Here we have 54 and -4, they add up to 50.
6i+36i = 42i.

End answer: 50 + -4i = 50-4i

Answer 10

no

Answer 11

thus why come and i ll teach u

Answer 12

ok sounds good i need the help bad

Answer 13

If i is not supposed to be sqrt(-1) then everything remails the same, only the part where i²=-1 is not to be done.

Then: 54+6i+36i+4i² = 4i²+42i+54 is the answer