What is the number of real solutions?
-11x^2 = x + 11

Question

What is the number of real solutions?
-11x^2 = x + 11

dumbcow · Answer

first set equal to zero

second find discriminate (b^2 -4ac)

third, if discriminate >0 : 2 real solutions
         if discriminate =0:  1 real solution
         if discriminate <0 :  no real solutions

angelwings996 · Answer

would the equation be -11x^2 - x - 11 = 0 ?

dumbcow · Answer

yes or you can get rid of the neg --> 11x^2 +x+11 = 0

angelwings996 · Answer

Okay, now what would I do?

dumbcow · Answer

find Discriminant http://en.wikipedia.org/wiki/Discriminant

hartnn · Answer

Compare your quadratic equation with $ax^2+bx+c=0$
find a,b,c
then calculate $b^2-4ac=...?$

angelwings996 · Answer

don't I already have a, b, and c so would I just substitute them into b^2  - 4ac ?

hartnn · Answer

what u got, a=..? 
b=...?c=..?

angelwings996 · Answer

doesn't a = 11, b = 1, and c = 11 ?

hartnn · Answer

thats correct, now as @dumbcow said, u just need to find whether b^2-4ac is positive or negative...

angelwings996 · Answer

so if I plug it in would it be like this ....
$$1 ^{2} - 4(11)(11)$$

hartnn · Answer

yes, go on.

angelwings996 · Answer

okay so $$1^{2} = 1 and -4(11) = -44(11) = -484$$
Then you would subtract -484 from 1 which gives you -483, right ?

hartnn · Answer

yes, so how many real solutions ?

angelwings996 · Answer

since -483 is less than 0 would it be no real solutions?

hartnn · Answer

absolutely correct :)

angelwings996 · Answer

Okay thank you so much for both of your helps!

hartnn · Answer

welcome ^_^