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Mathematics 19 Online
OpenStudy (anonymous):

√(100)

OpenStudy (tkhunny):

Have you considered "10"?

OpenStudy (anonymous):

can you show how you solved this to get this answer please

OpenStudy (tkhunny):

It's an eyeball problem. You should know the perfect squares. \(6^{2} = 36\) \(7^{2} = 49\) \(8^{2} = 64\) \(9^{2} = 81\) \(10^{2} = 100\)

OpenStudy (anonymous):

I'm new to solving equations like this, I was just trying to see how to solve the equation. It seems easy but hard to do

OpenStudy (tkhunny):

First, it's an expression, not an equation. That is an important distinction. Second, finding a square root can be a little tedious. As you appear to be rather new at it, your best current bet might be what is known as "Guess and Check". Given a little familiarity, like the short list I gave above, youcan make better guesses? Example: \(\sqrt{75} = ??\) Well, we know \(8^{2} = 64\) and \(9^{2} =81\) , so \(\sqrt{75}\) must be between 8 and 9.

OpenStudy (anonymous):

Oh ok thanks a lot. That really does help. So the square is normally always 2?

OpenStudy (anonymous):

ok thank you

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