less variability, more the average is representative of a set of data, how?
awww it's the simple question
Well if I'm reading this correctly, I would assume that variability is the amount by which the data varies. So if you have a bunch of data points near each other or if the data is more spread out. A measure of this isn't as useful as the average might be, since it doesn't tell you what it's varying away from...
Do you think my notion is correct that in case of extremely leptokurtic distribution the data values tend to cluster around the central value thus if we try and squeeze that distribution, all will be left is the cenral value itself. Hence less the variability, more will be the true respresentation of distribution by the averages. Moreover I guess if limits are applied on + & - sides then this can become a theorem. What do you say?
I say that you construct your sentences excessively ambiguous.
LOL because the question was ambiguous. I have to comment on that question.
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