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Algebra
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\[ \frac{e^{2y}-1}{e^{2y}+1} = x \] How can we solve for e^y ?
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First Cross Multiply
e^2y - 1 = x e^2y + x e^2y - x e^2y = x + 1 e^2y ( 1-x) = x + 1 e^2y = (x+1) / (1-x) e^2y = (e^y)^2 Take sqrt on both sides and u have e^y..:)
ie e^y = sqrt [ (x+1) / (1-x) ]
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