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In a G.P. , the first term is 7, the last term is 448, and the sum is 889. Find the common ratio and the number of terms.
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use an=a1*r^(n-1)
where an=48 and a1=7
*448
it is coming r^(n-1)=64
then i used the sum formula Sn=\[Sn =\frac{ a[r^n-1) }{ r-1 }\]
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exactly...now you got two equations in two unknowns...so solve for r and n
i am stuck here
where??tell me the second one
\[127=\frac{ r^n-1 }{ r-1 }\]
r comes out to be 2.isn't it??
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The answer should come r=2 and n=7
yeah hold on lemme write
ok
|dw:1356937412146:dw|
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