Question

\[\large{t^2+6t\over t-1}-{7\over t-1}\]

Answer 1

the answer is apparently \(t-7\) but i dont get how..im sure my brain's just not working but i still dont get it..

Answer 2

\(t+7\)*

Answer 3

\[\large{t^2+6t\over t-1}-{7\over t-1}\]
\[\frac{t^2+6t-7}{t-1}\]
Now factor the numerator, do you know how to do that? @yummydum

Answer 4

After you subtract, the top factors as

(t-1)(t+7)/(t-1)

t-1 cancels

Answer 5

see i told you i was being stupid... thanks @ash2326 and @CalebBeavers i see it now..forgot to put them under one denominator before factoring

Answer 6

Glad to help :D

Answer 7

:)