Question

f(x)=ln(x)+13(x)³-11(x)+cos(x), f'(x)=?

Answer 1

f'(x) = d(ln(x))/dx + d(13x^3)/dx - d(11x)/dx + d(cosx)/dx

Answer 2

Does it help?

Answer 3

ur r8 @sauravshakya

Answer 4

lets finish it

Answer 5

Do u know d(lnx)/dx = ???
@jadi

Answer 6

\(\huge \frac{d}{dx}\ln x=1/x \\ \huge \frac{d}{dx}x^n=nx^{n-1} \\\huge \frac{d}{dx}\cos x=-\sin x\)

Answer 7

@jadi

What did you get ?

Answer 8

looks like he is confused

Answer 9

It is easy lol.

Answer 10

Did u get this?
f'(x) = d(ln(x))/dx + d(13x^3)/dx - d(11x)/dx + d(cosx)/dx

Answer 11

@jadi

Please respond so we can help

Answer 12

he is sleeping !!1 where is he?

Answer 13

To find F'(x) we take the derivatives of each i.e
f'(x)=(ln(x))'+(13x3)'-(11x)'+(cosx)'-----Look x3 mean x cubic
=1/x+13*3x2-11-sinx------look!x2means x squr
=26x2-sinx+1/x-11----That's it!!!!

Answer 14

thanks guys i was just not there but i got it