Question

f(x)=2e^(-x),f'(X)=?

Answer 1

\(\huge \color{blue}{\frac{d}{dx}e^{ax}=ae^{ax}}\)

Answer 2

here a=-1 and 2can be factored out of derivative because its a constant.

Answer 3

@saifoo.khan , you meant \(\Huge {2e^{-x}[}{\frac{d}{dx} (-x)}]\)
right ?

Answer 4

-2e is the ans

Answer 5

now u know how to get \(-2e^{-x}\) as answer ?

Answer 6

Yes @hartnn . did a mistake. :D

Answer 7

no i m not get it

Answer 8

which part ?

Answer 9

-x will remain as power also?

Answer 10

yes, power will never change for e, it only gets multiplied before e term

Answer 11

ok

Answer 12

f'x=(2e-x)'=(2/ex)'=(2'ex-2(ex)')/(ex)2
=(-2ex)/(ex)2
=-2e-x --i think it is the answer!!!

Answer 13

this i got from chain rule,
\(\huge \color{blue}{\frac{d}{dx}e^{ax}=ae^{ax}}\)

Answer 14

Is the result u found is the same with me?

Answer 15

yes.

Answer 16

Thanks lol!