Simplify the expression csc^2x sec^2x/ sec^2 x + csc^2 x
This?\[ \large \frac{\csc^2(x) \sec^2(x)}{\sec^2(x)} + \csc^2(x) \]
csc^2 is in the denominator with sec^2
\[\Large \frac{ \csc^2x \sec^2x }{ \sec^2x + \csc^2 x }\]
Yes thats it
what basic identity can you remember that may help you simplify this problem?
reciprocal identity
sub them in the problem.
Im not really sure how to, can you please explain it?
\[ \sec^2(x) = \frac{1}{\cos^2(x)} \]So how about multiplying top and bottom bye \(\cos^2(x)\).
\[\Huge \frac{ \frac{ 1 }{ \sin^2x }\frac{ 1 }{ \cos^2x } }{ \frac{ 1 }{ \cos^2 x }+\frac{ 1 }{ \sin^2x } }\]
if you are familiar with @wio 's method, you can multiply both sides of the fraction by \[\Large \sin^2x \cos^2x\]
I am not can you explain it?
\[\frac{ \csc^2x \sec^2x }{ \sec^2x + \csc^2x }\cdot \frac{ \sin^2x \cos^2x }{ \sin^2x \cos^2 x }\]
multiply the numerators, multiply the denominators
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