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Biology 13 Online
OpenStudy (comrad):

Can someone help me? I'm in Biology9. 3. What is formed at the end of meiosis? (1 point)

OpenStudy (comrad):

two genetically identical cells four genetically different cells four genetically identical cells two genetically different cells

OpenStudy (anonymous):

wat unittt and lessson

OpenStudy (comrad):

u in CA?

OpenStudy (anonymous):

yes

OpenStudy (comrad):

U4 L18. its the practice thing

OpenStudy (comrad):

I need some help with some other stuff if you can.

OpenStudy (anonymous):

ok lemma check if i did it..........

OpenStudy (comrad):

ok

OpenStudy (anonymous):

srry im in unit 4 lesson 13 :(

OpenStudy (comrad):

aww. ill post the answers when im done. do u need help with anything?

OpenStudy (anonymous):

yea lol lesson 13

OpenStudy (comrad):

hold on. bio right?

OpenStudy (comrad):

goin into my gb now

OpenStudy (comrad):

Multiple Choice 1. Which of the following statements is true about gene regulation in prokaryotes? (1 point) (0 pts) Promoters determine whether a gene is expressed. (0 pts) Expressed genes make more DNA. (1 pt) DNA-binding proteins determine whether a gene is expressed. (0 pts) RNA polymerase regulates gene expression 1 /1 point 2. A lac repressor turns off the expression of the lac genes by (1 point) (0 pts) binding to the promoter. (0 pts) binding to DNA polymerase. (1 pt) binding to the operator. (0 pts) binding to the lac genes. 1 /1 point 3. When E. coli is grown on glucose, and there is no lactose available (1 point) (0 pts) lactose molecules bind to the lac repressor. (1 pt) the lac repressor binds to the operator of the lac operon. (0 pts) RNA polymerase binds to the promoter of the lac operon. (0 pts) the lac genes are transcribed into messenger RNA. 1 /1 point 4. What is the function of the operator in an operon? (1 point) (1 pt) Provide a site on the DNA where the repressor can bind and stop transcription. (0 pts) Provide a site on the DNA where RNA polymerase can bind to begin transcription. (0 pts) Code for the repressor protein. (0 pts) Code for the RNA polymerase protein. 1 /1 point

OpenStudy (anonymous):

ok

OpenStudy (comrad):

there ya go

OpenStudy (anonymous):

thanks lol

OpenStudy (comrad):

is that all jessica?

OpenStudy (comrad):

hello

OpenStudy (anonymous):

ok how bout lesson 14 plzzz

OpenStudy (comrad):

ok

OpenStudy (comrad):

im wont give u the exact answers im just gonna help

OpenStudy (anonymous):

thanks

OpenStudy (comrad):

my slow teacher is still grading it, i think i rememmber the multiple choice ones tho

OpenStudy (anonymous):

yaay

OpenStudy (comrad):

lol, gimme a minute

OpenStudy (comrad):

regulation of the gene right?

OpenStudy (anonymous):

yea

OpenStudy (comrad):

I think all of the above for the first one.

OpenStudy (comrad):

argh two headed monster!

OpenStudy (anonymous):

lol

OpenStudy (comrad):

I don't really know.

OpenStudy (comrad):

sorry jess

OpenStudy (comrad):

ur behind huh?

OpenStudy (comrad):

do u know this 8. If a mutation occurs in the gene for the lac repressor and results in a repressor that does not bind lactose, which of the following will be observed? (1 point) The mutant will not be able to grow on lactose. The mutant will only be able to grow on lactose. The mutant will be able to grow on lactose and on other sugars. The mutant will be harmed by the presence of lactose.

OpenStudy (anonymous):

no

OpenStudy (comrad):

that sux

OpenStudy (tyteen4a03):

Not sure how many questions are actually there, but here you go: 1. four genetically different cells. During meiosis genes from the maternal cell and the parental cell does a switcheroo and therefore the cells will contain different genes. During meiosis 4 cells are created from 2 cells. 8. Only guessing: The mutant will not be able to grow on lactose.

OpenStudy (matt101):

For question #8, a little background - the lac operon is a set of genes used by bacteria to metabolize lactose and use it for energy/nutrients. In such bacteria, glucose may be the normal energy source, and genes of the lac operon are not transcribed (due to the action of the lac repressor). This prevents the bacteria from wasting resources manufacturing unnecessary proteins (an energy-expensive process). However, in an environment where lactose is available but glucose is not, the lac operon is activated by removal of the lac repressor, and lactose can then be metabolized by the cell. The lac repressor is removed upon binding lactose, which stabilizes it in a conformation that does not bind to DNA and in this way allows transcription to proceed. Now to answer the question (@Comrad, @jessica90210): if there is a mutated lac repressor that cannot bind lactose, it cannot dissociate from the lac operon, even in a lactose-rich environment. This means genes whose products are involved in lactose metabolism are not transcribed, and so the bacteria will be unable to grow on lactose alone. @tyteen4a03, you were right :) Hopefully this explanation helped everyone out, but let me know if I need to clarify anything. I've done university-level courses in molecular biology and microbiology, so I'm happy to help with other questions you may have!

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