Question

If sum of the roots is \(p\) & the sum of their square is \(q^2\) the equation is :-

Answer 1

hint : \((a+b)^2=a^2+b^2+2ab\)
you can find product of roots from here.

Answer 2

a+b=p
a^2+b^2=q^2

Answer 3

sorry but i couldn't understand it very well :(

Answer 4

only gt u a little :(

Answer 5

Consider 'a' and 'b' are the roots of the equation.

Answer 6

So their sum is p

a+b=p

Answer 7

you got the equation if 1st comment, right ?
substituting the values.
\(ab=(p^2-q^2)/2=product \: of \: roots\)

Answer 8

now u have sum and product, can u find the equation ??

Answer 9

\(x^2-sum*x+product=0\)

Answer 10

\[x^2-(S.O.R)x+(P.O.R)=0\]

Answer 11

ohh k i gt it

Answer 12

Thanx both of u a lot :)

Answer 13

welcome ^_^

Answer 14

Welcome :)