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what are the zeros of f(x) = 2x^3 -10x^2 +7x-35
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Write \[0=2x ^{3}-10x ^{2}+7x-35\]and then solve for x.
The other thing you can do is factor the equation to a form that looks like f(x)=(x+a)(x+b)(x+c) Then -a, -b, and -c will be the 0s.
put x=5 in this equation nd u will get 0 so your one solution is (x-5) then divide x-5 with ur equation 2x^3-10x^2+7x-35
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