Give an example of an even function and explain algebraically why it is even.
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Parth (parthkohli):
So, an even function \(f\) is a function where for all \(x\), \(f(x) = f(-x)\). The square function and the absolute-value functions are pretty cool examples.
OpenStudy (anonymous):
is that it?
Parth (parthkohli):
Maybe.
Parth (parthkohli):
Do you know what \(|x|\) is?
OpenStudy (anonymous):
x
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Parth (parthkohli):
And \(|-x|\).
OpenStudy (anonymous):
x
Parth (parthkohli):
Bang on!
Parth (parthkohli):
And do you know what \((-x)^2\) is?
OpenStudy (anonymous):
x?
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Parth (parthkohli):
Nope
OpenStudy (anonymous):
o
OpenStudy (anonymous):
x^2
Parth (parthkohli):
Yes.
Parth (parthkohli):
That's correct! =)
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OpenStudy (anonymous):
so how does that answer this question, bro? :)
Parth (parthkohli):
You just answered the question, “explain algebraically why it is even”.
Look back at the definition.
OpenStudy (hba):
If
f(-a)=f(a) then it is even
example
f(x)=x^2
f(-x)=(-x)^2
f(-x)=x^2
therfore,
f(x)=f(-x)
@parth explained it well :)
OpenStudy (hba):
@ParthKohli *
Parth (parthkohli):
:)
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Parth (parthkohli):
Let me do that for an absolute-value function too! So we define the absolute value function as follows\[f(x) = \cases{x \ \ \text{iff} \ \ x >0 \\ -x \ \ \text{iff} \ \ x < 0 }\]It is clear that \(f(-x)=f(x)=x\), hence an even function.