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What is the derivative of f(x)=l x l at x=0? a) 1 b) -1 c) 0 d) Does not exist.
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then ofcourse it should be -1, right?
not sure,.....if f'(x) = -1, if x < 0; f'(x) = 1, if x > 0
from another angle....x-->p- means from the left (or negative side). x-->p+ means from the right (or positive side). But limit |x| = limit of -x = -1 at p (the slope of the line) . x-->0- limit |x| limit of x = +1 at p (the slope of the line) . x-->0+ Since there is no unique limit at 0 for f(x) = |x|, then f(x) = |x| has no derivative at 0
thanks for your valuable tips.....
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