Mathematics
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OpenStudy (anonymous):
help please(: 1 over 3 (2x − 8) = 4
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OpenStudy (anonymous):
\[\frac{1}{3(2x-8)}=4\]
What do you suggest from here?
OpenStudy (hba):
\[\frac{ 1 }{ 3(2x-8) }=4\]
Use distributive property to evaluate your denominator
OpenStudy (anonymous):
@Limitless its 1 over 3 and next to (2x − 8) = 4
OpenStudy (anonymous):
\[\frac{1}{3}(2x-8)=4\]
What do you suggest from here?
OpenStudy (anonymous):
@Limitless distributing?
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OpenStudy (hba):
\[\frac{ 1 }{ 3 }(2x-8)=4\]
1)Multiply both sides by 3
OpenStudy (anonymous):
@sylinan Sure. Then what?
OpenStudy (anonymous):
@hba doesnt it cancel out?
OpenStudy (hba):
Yes.
OpenStudy (anonymous):
You get \[\frac{2}{3}x-\frac{8}{3}=4.\]
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OpenStudy (hba):
@Limitless
Stop complicating it.
OpenStudy (anonymous):
im getting confused ):
OpenStudy (hba):
Multiply your question by 3
OpenStudy (anonymous):
@hba Complicating it would be using the Taylor series for \(x\). I apologize for replying when she was talking to you; I misread the post.
OpenStudy (hba):
@sylinan \[\frac{ 1 }{ 3 }(2x-8)=4\]
Multiply both sides by 3.
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OpenStudy (hba):
\[3 \times\frac { 1 }{ 3 }(2x-8)=4 \times 3\]
OpenStudy (hba):
@sylinan
I know you can do it now :)
OpenStudy (anonymous):
@hba okay so far i got 3(2x-8)=12
OpenStudy (hba):
Now see this
\[\ \cancel 3 \times \frac{ 1 }{\ \cancel 3 }(2x-8)=4 \times 3\]
OpenStudy (anonymous):
so then its 1(2x-8)=12?
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OpenStudy (hba):
Now add both sides by 8
OpenStudy (anonymous):
i thought i was suposed to do distribute the one?
OpenStudy (hba):
It doesn't make a diff
It will stay the same :)
OpenStudy (anonymous):
true okay so i got x=10?
OpenStudy (hba):
Yeaahhhh :D
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OpenStudy (hba):
You are right :P
OpenStudy (anonymous):
thank you (: help me with one more?(:
OpenStudy (hba):
Sure,Please post your question in a new tab :)
OpenStudy (anonymous):
okay so open a new question?
OpenStudy (hba):
Yeah.
The CoC says that not me :P
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OpenStudy (anonymous):
oh okay (: