Question

simplify the complex rational expressions: show work please

√x 1
--- - ---
1 6√x
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√x

Answer 1

First, write the two fractions in the numerator as one, using\[\frac{ a }{ b }+\frac{ c }{ d }=\frac{ ad+bc }{ bd }\](sounds familiar?)
So:\[\frac{ \sqrt{x} }{ 1 }-\frac{ 1 }{ 6\sqrt{x} }=\frac{ 6(\sqrt{x} )^2-1}{ 6\sqrt{x} }=\frac{ 6x-1 }{ 6\sqrt{x} }\]Now, instead of dividing by √x, multiply with the inverse:\[\frac{ 6x-1 }{ 6\sqrt{x} }\cdot \frac{ 1 }{ \sqrt{x} }=\frac{ 6x-1 }{ 6(\sqrt{x})^2 }=\frac{ 6x-1 }{ 6x }\]and you're done!

Answer 2

the choices are
a) x^2- 1/6x
b) (√x/1) - (1/6√x) / √x
c) 1-1/6
d) 1-1/6x

Answer 3

Look's like someone answered for you

Answer 4

yep

Answer 5

not correct.

Answer 6

Did you try working it out yourself first?
Sometimes answers may not match exactly because they are written in a different form, but essentially mean the same thing.

Answer 7

go to myalgebra.com and type it in... i have a feeling it is D

Answer 8

yes i tried but i had no clue what to do and okay

Answer 9

Peachy, can you show us what you did in your work and we can check where you are stuck on? That way we can guide you in the right direction :)

Answer 10

we? lol abbot your better than me hehe

Answer 11

@blondie16 I believe that you are capable of doing this problem too. I have no doubt in my mind.

Answer 12

lol well than juu hehe

Answer 13

"not correct" is not correct ;)
One could take another step:\[\frac{ 6x-1 }{ 6x }=\frac{ 6x }{ 6x }-\frac{ 1 }{ 6x }=...\]But written as as one fraction also has its charm.