Question

A train, starting at 11 am, travels east at 45 mph while another, starting at noon from the same point, travels south at 60 mph. How fast are they separating at 3pm?

Answer 1

Pythagorean theorem

Answer 2

how

Answer 3

go ahead and plug in your values to find out how fast each is separating in it's direction, use a^2 + b^2 = c^2 to find how fast the distance between them is increasing

Answer 4

just think about the trains as vectors

Answer 5

i got 75

Answer 6

show the steps please!

Answer 7

\[(45+x)^2+y^2=d^2\]
\[2(45+x)x'+2yy'=2dd'\] you want \(d'\) and you are told \(x'=45,y'=60\)
plug in the numbers, solve for \(d'\)

Answer 8

why it is 45+x

Answer 9

because it had a 45 mile head start

Answer 10

then what is x and y

Answer 11

i will let you figure that out
you know the speed, you know the time, therefore you know the distance

Answer 12

d=v*t

Answer 13

what is the time

Answer 14

3 pm according to the question