Question

If 2^(16x^2-8x-3)=1, what does x equal?

Answer 1

Explanation please

Answer 2

can somebody please help me with my problem? sorry to bother

Answer 3

\[\large 2^{(16x^2-8x-3)}=1\]\[\large \log_22^{(16x^2-8x-3)}=\log_21\]\[\large (16x^2-8x-3) \log_22=\log_21\]\[\large \log_22=1, \space \log_21=0\]\[\large 16x^2-8x-3=0\]Now factor to solve for x or use the quadratic (suggested method)

Answer 4

-1/4 and 3/4?

Answer 5

@ChmE Am i right?

Answer 6

I don't know I haven't did it

Answer 7

Seems right !!

Answer 8

cool,thanks for the help :) Happy New Years!

Answer 9

Post the quick way then plz @Hero

Answer 10

That is true, at least now they see how to do it, if that wasn't recognized right away