a lead bullet (9g) moving at 750m/s hits a target at rest on a smooth surface, it get stuck in the target. the bullet temp increases by 300K. The collision is inelastic, and the target did not heat up find the mass of the target. the enery to heat 1kg of lead by 1k is 130j

Question

a lead bullet (9g) moving at 750m/s hits a target at rest on a smooth surface, it get stuck in the target. the bullet temp increases by 300K. The collision is inelastic, and the target did not heat up find  the mass of the target. the enery to heat 1kg of lead by 1k is 130j

shubhamsrg · Answer

let mass of target be M
since its inelastic collision ,both move together in the end with common velocity
conserving momentum,
(0.009)(750) = (0.009 +M)v

calculate v from here..
then use conservation of energy..

shubhamsrg · Answer

initial energy = kinetic energy of bullet
final energy = heat energy + kinetic energy of bullet+target..

anonymous · Answer

it is an inelastic collision so kinetic energy of the bullet will not be conserved right? so only the bullets temperature goes to the kinetic energy ?

shubhamsrg · Answer

total energy will always be conserved
the heat energy generated will result in increase in temperature..
there will be decrease in kinetic energy,ofcorse,that difference must have been utilised to convert it into heat ,or to inc temp

anonymous · Answer

sorry i forgot to state the block does not heat up