calculate the molarity & normality of a solution containing 0.5gm of NAOH dissloved in 500ml solution.

Question

anonymous · Answer

@DLS ,@sauravshakya @saifoo.khan

anonymous · Answer

@sauravshakya

dls · Answer

$$\LARGE Molarity=\frac{Number \of\moles}{Volume}$$

dls · Answer

Can you calculate the number of moles of NaOH in 0.5 grams?

australopithecus · Answer

Molarity = $$Molarity = \frac{Moles}{LitresOfSolution}$$



Normality is used to express acid/base equivalents, so it is referring to the amount of  H+ or OH- that can be released from a single molecule, so it is not looking at the molecule as a whole. This is useful for acid base titrations and other reactions.

We use this equation to find Normality

$$Normality = Molarity(Equivalents)$$

To figure out Normality you simply need to divide by equivalents.


EXAMPLES:

So just say you have 1M of HCl, it has an equivalency of 1 because 1mole of HCl gives 1mole of H+

so,

1M*1equivilant = 1N

So just say you have 2M of H2SO4, it has an equivalency of 2 because 1mole of H2SO4 can give off 2mole of H+

so,

4M*2equivialents = 4N

So just say you had 4M of H3PO4, it has an equivalency of 3 because 1mole of H3PO4 can give off 3mole of H+

so,

4M*3equivalents = 12N



Hope this helps if you have any questions feel free to ask