Question

Just for fun. :)
\[\int_{0}^{\pi/2}xcot(x)dx\]

Answer 1

is the answer \(\pi^3\)/24 ???

Answer 2

square root of that

Answer 3

Nope!!!

Answer 4

It cannot be that easy!!

Answer 5

(1/2) pi ln(2)

Answer 6

oh, yes...
\(I=\int_{0}^{\pi/2}x\cot(x)dx \\I=\int_{0}^{\pi/2}(\pi/2-x)\tan(x)dx\)
now multiply both equations to eliminate trignometric function

Answer 7

@Mimi_x3


Please respond.

Answer 8

hba, your answer is correct.

Answer 9

did u integrate by parts

Answer 10

Soryy!! Faster than expected!!

I think @hba cheated :)

Answer 11

you think ? i know :P

Answer 12

I did not solve it guys.

Answer 13

Some one else solved it for me.

Answer 14

:P

Answer 15

It was obv :P

impossible to solve it in a couple of seconds.

Answer 16

oh, the catch was to add, not multiply :P
hba, wolf.

Answer 17

Yes @hartnn Yes :P

Answer 18

@Callisto Why did you not comment ?

Answer 19

My comment...
@hartnn @Mimi_x3 ♥♥♥